11x+4.9x^2-35=0

Solution for 11x+4.9x^2-35=0 equation:

11x+4.9x^2-35=0

a = 4.9; b = 11; c = -35;
Δ = b2-4ac
Δ = 112-4·4.9·(-35)
Δ = 807
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{807}}{2*4.9}=\frac{-11-\sqrt{807}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{807}}{2*4.9}=\frac{-11+\sqrt{807}}{9.8}
$